一个小数是0.123123123……无限循环,其小数点后1位是1、后2位是2,依此类推,求第N位的值。横线处应填入的代码是( )。
int N; cin >> N; remainder = ______________; if (remainder == 0) cout << 1; else if (remainder == 1) cout << 2; else cout << 3;
N % 3
(N - 1) % 3
N / 3
(N - 1) / 3