执行如下 C++ 代码，将从小到大依次输出 abs(N) 个整数，并在最后输出 1。

int N;
cin >> N;
int start_num = 1, end_num = N + 1, i;

if (N < 0)
    start_num = N, end_num = 0;

for (i = start_num; i < end_num; i++)
    cout << i << " ";

cout << endl << ((i - 1) == abs(N)) << endl;